The electric field in a region is given by ve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electric field is given by $\vec E = \frac{3}{5}E_0\hat i + \frac{4}{5}E_0\hat j$.Given $E_0 = 2 	imes 10^3 \, N/C$,the electric field is $\v

Vedclass · Accepted Answer

$240$

Vedclass · Answer

(A) The electric field is given by $\vec E = \frac{3}{5}E_0\hat i + \frac{4}{5}E_0\hat j$.Given $E_0 = 2 	imes 10^3 \, N/C$,the electric field is $\vec E = \frac{3}{5}(2 	imes 10^3)\hat i + \frac{4}{5}(2 	imes 10^3)\hat j = 1200\hat i + 1600\hat j \, N/C$.The surface is parallel to the $y-z$ plane,so its area vector $\vec A$ is directed along the $x$-axis: $\vec A = 0.2\hat i \, m^2$.The electric flux $\phi$ is given by the dot product $\phi = \vec E \cdot \vec A$.$\phi = (1200\hat i + 1600\hat j) \cdot (0.2\hat i) = 1200 	imes 0.2 = 240 \, N \cdot m^2/C$.

The electric field in a region is given by $\vec E = \frac{3}{5}E_0\hat i + \frac{4}{5}E_0\hat j$ and $E_0 = 2 \times 10^3 \, N/C$. Then,the flux of this field through a rectangular surface of area $0.2 \, m^2$ parallel to the $y-z$ plane is ...... $\frac{N \cdot m^2}{C}$.

Similar Questions

$A$ sphere of radius $R$ has a charge $Q$. $A$ concentric spherical Gaussian surface of radius $2R$ is drawn. The electric flux associated with the Gaussian surface is ........

The number of lines of force originating from a point charge of $2 \times 8.85 \times 10^{-9} \text{ C}$ in a medium of dielectric constant $10$ is $(\epsilon_0 = 8.85 \times 10^{-12} \text{ SI unit})$.

The distribution of some charges on two Gaussian surfaces $A$ and $B$ are as shown in the figure. If $\phi_A$ and $\phi_B$ are electric fluxes linked with the surfaces $A$ and $B$ respectively,then $\frac{\phi_A}{\phi_B}=$

$A$ uniformly charged conducting sphere of diameter $3.5 \ cm$ has a surface charge density of $20 \ \mu C \ m^{-2}$. The total electric flux leaving the surface of the sphere is nearly:
[permittivity of free space,$\epsilon_0 = 8.85 \times 10^{-12} \ SI \ unit$]

$A$ charge $q$ is located at the centre of a cube. The electric flux through any face is

Vedclass Test Series

Exam Paper Generator

Online Exam Module